日期:23-04-04 时间:02:31 来源: 益荣金属
当Ψ(t)=0时,夹芯板的中心点处达到最大挠度。
3-58式两边分别求导,得到:
Ψ(t)=-[√(12N0/mL3)]·[w1+w2+(M0U+M0C)/N0]·sin[√(12N0/mL3)](t-T2’)
+v1cos[√(12N0/mL3)](t-T2’)
求Ψ(T’)=0,解得板的响应时间为
T’=T2’+[√(mL3/12N0)]tan-1 v1/〔[√(12N0/mL3)][w1+w2+(M0U+M0C)/N0]〕 (3-60)
将3-60式代入3-58式,得到板中心点的最终挠度为:
W(T)={√[v1√(mL3/12N0)]2+[w1+w2+(M0U+M0C)/N0]2}-(M0U+M0C)/N0 (3-61)
因此,多孔金属夹芯板在泡沫铝金属子弹撞击下,板中心点的最终挠度和响应时间分别为:
应用外接正方形屈服条件:
W(T)={√[3R2v1/L2·√(mL3/12N0)]2+[w1+w2+(M0U+M0C)/N0]2}-(M0U+M0C)/N0
T=T2+[√(mL3/12N0)]tan-1 ·3R2v1/{L2[√(12N0/mL3)][w1+w2+(M0U+M0C)/N0]}
R/L<1/(√2)时, (3-62)
W(T)={√[v1√(mL3/12N0)]2+[w1+w2+(M0U+M0C)/N0]2}-(M0U+M0C)/N0
T’=T2’+[√(mL3/12N0)]tan-1]·〔v1/〔[√(12N0/mL3)][w1+w2+(M0U+M0C)/N0]〕
R/L>1/(√2)时, (3-63)
应用内接正方形屈服条件:
W(T)={√[3R2v1/L2·√(mL3/12ζN0)]2+[w1+w2+(M0U+M0C)/N0]2}-(M0U+M0C)/N0
T=T2+[√(mL3/12ζN0)]tan-1 ·3R2v1/{L2[√(12ζN0/mL3)][w1+w2+(M0U+M0C)/N0]}
R/L<1/(√2)时, (3-64)
T’=T2’+[√(mL3/12ζN0)]tan-1]·〔v1/〔[√(12ζN0/mL3)][w1+w2+(M0U+M0C)/N0]〕
R/L>1/(√2)时, (3-65)
其中ζ=0.5
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